Which graph represents -5x+4y > -1

Mathematics

1 answer:

Nikitich [7]3 years ago

8 0

Answer:

Were is the graph

Step-by-step explanation:

show me the graph

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Write 1,386 as the product of its prime factors. A. 2 x 693 B. 2 x 3 x 7 x 33 C. 2 x 3 x 3 x 7 x 11 D. 2 x 3 x 231

Lemur [1.5K]

2 / 1386
3 / 693
3 / 231
7 / 77
11/ 11
/ 1

Prime factors = 2*3*3*7*11

Option C.

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3 years ago

Anyone know how to figure this out. I need the answer by 7:30 tonight.

Sholpan [36]

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4 years ago

Which of the following are identities? check all that apply.

Feliz [49]

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

$(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x$

$(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)$

$(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x$

$(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x$