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2 years ago

Which graph represents -5x+4y > -1

Mathematics

1 answer:

Nikitich [7]2 years ago

8 0

Answer:

Were is the graph

Step-by-step explanation:

show me the graph

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93^2 -83^2<br><br> SMART CALCULATED

12345 [234]

Answer:

Step-by-step explanation:

-1760 is the answer 83 times 83 minus 93 times 93 is -1760

8 0

2 years ago

Mr. Gutierrez had $100 to purchase candy for his students that completed their work. He

Sidana [21]

Answer:

$21.50

Step-by-step explanation:

Mr. Gutierrez had $100 to purchase candy for his students that completed their work.

He bought 8 bags of jolly ranchers

Each bag of jolly ranchers cost $3.25.

Hence, the cost of 8 bags of jolly ranchers = 8 × $3.25

= $26

He also bought 25 bags of assorted chocolate and each bag of assorted chocolate cost $2.10.

Hence, the cost of 25 bags of assorted chocolates = 25 × $2.10

= $52.5

Therefore, the amount of money Mr. Gutierrez has left over after these purchases is calculated as:

Total amount - Sum of ( Cost of 8 bags of jolly ranchers + 25 bags of assorted chocolates)

= $100 - ( $26 + $52.5)

= $100 - $78.50

= $21.50

7 0

2 years ago

Grocery Mart has cookies on sale for $3 for 12 cookies. Food Shoppe has cookies on sale for $5.70 for 19 cookies. Which store ha

AnnZ [28]

Answer:

5.70 for 19

Step-by-step explanation:

4 0

3 years ago

Whoever checks my work and tell what I did wrong and the right answer will

gulaghasi [49]

Answer:

See below

Step-by-step explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolating $d_{1}$ , we need to get rid of the 1/2 first. Let's multiply each side by 2:

$2*m = 2*\frac{1}{2}(d_{1}+ d_{2}) \\2m = d_{1}+ d_{2}$

After this, we just subtract $d_{2}$ from each side to get $d_{1}=2m- d_{2}$ . Dark Blue is correct! Let's now plug in those numbers below:

$d_{1}=2(10)- 13 = 20-13=7$

G: Let's isolate the vw^2 on one side by subtracting y from each side:

$vw^{2} +y-y=x-y\\vw^{2}=x-y$

Let's now divide each side by v, then put each side under a square root to get our final answer:

$\frac{vw^2}{v} = \frac{x-y}{v}\\ w^2 = \frac{x-y}{v}\\\sqrt{w^2} = \sqrt{\frac{x-y}{v}} \\w=\sqrt{\frac{x-y}{v}}$

Orange is correct! Again, let's solve the problem underneath:

w= $w=\sqrt{\frac{38-(-7)}{5}} = \sqrt{\frac{38+7}{5}} = \sqrt{\frac{45}{5}}=\sqrt{9}=3$

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

$2a-2a+3c=17a-2a+21\\3c = 15a+21\\\frac{3c}{3} = \frac{15a+21}{3}\\c = \frac{15a}{3}+ \frac{21}{3} \\c = 5a+7$

Purple is correct! Let's solve the problem:

$c = 5(\frac{16}{5})+7 = 16+7 = 23$

7 0

2 years ago

Write the standard form of an equation of an ellipse subject to the given conditions.

irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

$\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1$

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

$\frac{x^2}{1369}+ \frac{y^2}{1394} =1$

6 0

2 years ago