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3 years ago

12

Find the area of the rectangle. 2X+3 X+1

2 answers:

TiliK225 [7]3 years ago

6 0

Answer: 2x squared + 5x + 3
Explanation: 2x+3(x+1)
2x(x+1) +3 (x+1)
2x (squared) + 2x + 3x + 3

hope that helps if u have any questions let me know also are u sure that this is the full question because it doesn't really make sense like it doesn't give any measurements at all so you can't really find the area you can only simplify the equation??
if there is any more information about this question comment under this and i will solve it fully!!

andriy [413]3 years ago

3 0

Answer:

Doesn't seem like a rectangle but when you combine like terms you get 5x+1

sorry if it didn't help.

Step-by-step explanation:

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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3 years ago