The graph of y = f(x) is the solid black graph below. Which function represents the dotted graph?

Mathematics

1 answer:

nevsk [136]3 years ago

6 0

Answer:

C (The lower left one)

Step-by-step explanation:

I saw that the vertex was equal to (-1,1) and that is the only answer that makes sense

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The figure shows two triangles on the coordinate grid: A coordinate grid is shown from positive 6 to negative 6 on the x-axis an

mihalych1998 [28]

Check the picture.

since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.

The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.

We see that the distance CC'' is 5.

So

Answer is:

"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"

8 0

3 years ago

Read 2 more answers

What is the weekly earnings of $4.75 per hour, 37 hours if all hours over 50 are paid time and a half?

Stels [109]

37* 4.75 =175.75

no overtime since there are no hours over 50

Answer: $175.75

7 0

3 years ago

PLEASE HELP!!! very confused

Leni [432]

Answer:

Step-by-step explanation:

The vertices lie on the x-axis, as is determined by their coordinates. This makes the center of this hyperbola (0, 0) because the center is directly between the vertices. The fact that the foci also lie on the x-axis tells us that this is the main axis. What this also tells us is which way the hyperbola "opens". This one opens to the left and the right as opposed to up and down. The standard form for this hyperbola is:

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$ and so far we have that h = 0 and k = 0.

By definition, a is the distance between the center and the vertices. So a = 5, and a-squared is 25. So we're getting there. Now here's the tricky part.

The expressions for the foci are (h-c, k) and (h+c, k). Since we know the foci lie at +/-13, we can use that to solve for c:

If h+c = 13 and h = 0, then

0 + c = 13 and c = 13.

We need that c value to help us find b:

$c^2=a^2+b^2$ and