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3 years ago

Please help me..........

Mathematics

2 answers:

Gwar [14]3 years ago

8 0

Answer: 9, it is the average of all the middle of all the numbers

Step-by-step explanation:

hoa [83]3 years ago

7 0

Answer:
9
step-by-step explanation:
10 + 7 + 9 + 11 + 8
45/5
9

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4 years ago

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The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in

garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

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3 years ago

Television viewers cast votes to decide the winners in different rounds of a singing competition. The number of votes cast in th

Mashutka [201]

Answer:

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3 years ago

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A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin

maks197457 [2]

Answer:

(a) $\sum x_i=56.68$ and $\sum x_i^2=197.46$

(b) The sample variance is $s^2=0.530$ and the sample standard deviation is $s=0.728$

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

$\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68$

and the sum of their squares is

$\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46$

(b)

The sample variance, denoted by $s^2$ , is given by

$s^2=\frac{S_{xx}}{n-1}$

where $S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}$

Applying the above formula we get that

$S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482$

$s^2=\frac{8.482}{17-1}=0.530$

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

$s=\sqrt{s^2}$

Applying the above formula we get that

$s=\sqrt{0.530}=0.728$

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3 years ago

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Answer:

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