1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3
If I'm doing this correctly, you would need to multiply everything inside the parenthesis by 8. So it would be 8x-24y·8x+24y. I'm sorry if that's not right, but that is my interpretation of the problem. Hope I was of some assistance :)
Answer:
-1
Step-by-step explanation:
We need to find the value of tan² 70° -sec² 70°.
We know that,
...(1)
We can write the given expression as :
tan² 70° -sec² 70° = -(-tan² 70° +sec² 70°)
=-(sec² 70°-tan² 70°)
Using identity (1)
=-(1)
= -1
Hence, the value of the given expression is -1.
28. 5T<1.5 is the answer. would you like 27 too?
First we expand the brackets:
-2a + 8 + 6a = 36
4a + 8 = 36
We then need to get the a's onto one side and the numbers onto the other:
4a = 28
We can then divide to get an x by itself:
a = 28/4 = 7
