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3 years ago

The table shown below represents a function. Which of the following values could not be used to complete the table?

Mathematics

1 answer:

skad [1K]3 years ago

4 0

Answer:

may be

15 is the answer

hope it help uh

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If sin(6m-8) = cos (2m), find the value of m.

Gala2k [10]

We believe that the angles are in quadrant 1.

<span>sin(6m-8) = cos (2m)

</span>⇒ 6m-8 = 90 - 2m
<span>
6m + 2m = 90 + 8

8m = 98

m = 98 / 8 = 12.25

</span>

4 0

3 years ago

A number line going from 0 to 1. There are 6 equal spaces between 0 and 1. The line contains 0, A, B, blank, C, D, 1.

TiliK225 [7]

Answer:

The number line is divided by 6ths.

Step-by-step explanation:

There are 6 equally sized spaces between 0 and 1 on a number line. By definition of a fraction, a quantity is divided upon a number of equal parts in which can be expressed as the number of parts divided by the total number of parts. Therefore, the numerator in this case will be how many of the 6 parts are there at a certain point; the denominator will be 6, since there are 6 total, equal parts. In this case, think of the fraction as a distance traveled from 0 to 1 in 6 parts; the numerator is how far is traveled, and the denominator is the total travel distance. Point A is located at 1/6, since it is 1 out of the 6 pieces traveled. Point D would be at 5/6 because it has traveled 5 out of the 6 distances.

6 0

2 years ago

Read 2 more answers

Determine the equation of the graph, and select the correct answer below.

Hunter-Best [27]

Vertex is (h,k)
Equation is ..
Y = (x -h)^2 + k
Put in vertex (-4,-1) gives the equation
Y = (x+4)^2 - 1

8 0

3 years ago

Y=5^× what happens as the x value increases by 1

Allisa [31]

Answer:

Step-by-step explanation:

It continues to go up in the positive X and Y Axis. Like an exponential function

8 0

3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

3 years ago