Here is the answer to the given problem. So, what Christina wants to find out is the sum of the length after 10 throws given that in each throw, it retracts 70% of the original length. So to continue the given data, here are the results:
4: 1.029
5: 0.7203
6: 0.50421
7: 0.352947
8: 0.2470629
9: 0.17294403
10: 0.12106082
Since she wants to find the sum of the length after 10 throws, we are just going to add the lengths above. So the answer would be this: 9.71752475. To round this off to the nearest hundredth, the answer would be 9.72. Hope this helps.
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
C
Step-by-step explanation:
