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defon
3 years ago
9

I NEED HELP PLZ I WILL GIVE THANKS AND BRAINLIST

Mathematics
1 answer:
ratelena [41]3 years ago
7 0

Answer:

Point B

Step-by-step explanation:

Inside the darkest part where both inequalities are true

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I need an answer ASAP with an explanation please!
Butoxors [25]

Answer:

y intercept (0;4)

Step-by-step explanation:

let x = 0 because the graph will intersect the y-axis at the value of 0 for the x-axis

3 0
3 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Hai came someone help I too lazy to do it...
baherus [9]

Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}   Transform the Expressions

\frac{1+1}{4} +\frac{3+3+5+5+5+7}{8}    Calculate the sum

\frac{2}{4} +\frac{28}{8}    Reduce

\frac{1}{2}+\frac{7}{2}   Transform the Expression

\frac{1+7}{2}   Calculate

\frac{8}{2}  Reduce the Fraction

4

Please mark brainliest if this helped you :)

3 0
3 years ago
Help with this math question please
kvv77 [185]
First question.

We will build up the 3-dimensional object from the dimensions shown in the view above. In doing this, the object is as shown in figure 1. So, we need to find the volume of this object. Let's cut off this object into two objects, so in doing this we can find the whole volume as the sum of the volume in green plus the volume in red (both are cubes), so:

V_{t} = V_{g}+V_{r} = 8 \times 3 \times 5 + 8 \times 5 \times 8  = 440 ft^{3}

So the answer is G.

Second question

The answer is D. Let's analyze it:

Given that r represents the radius  of the pizza and n the number of slices, so if we substitute r in this equation, then the values for n are:

n =  r^{2}+1

n=2^{2}+1=5
n=4^{2}+1=17
n=5^{2}+1=16
n=8^{2}+1=65
n=10^{2}+1=101

These are the values of n shown in the table above.

6 0
4 years ago
31=4-9y I need help sorry
Drupady [299]

Answer:

y=-3

Step-by-step explanation:

31=4-9y

9y=4-31

9y=-27

y=-27/9

y=-3

8 0
3 years ago
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