Answer:
13v + 2b = 211
4v + 4b = 268
#students each VAN can carry: 7
#students each BUS can carry: 60
Step-by-step explanation:
Let v = number of students in each van.
Let b = number of students in each bus.
High School A:
13v + 2b = 211
High School B:
4v + 4b = 268
The system of equations is
13v + 2b = 211
4v + 4b = 268
We will solve this system of equation with the addition method.
Write the first equation as it is. Divide both sides of the first equation by 2 and write it below the first equation. Then add the equations.
13v + 2b = 211
(+) -2v - 2b = -134
----------------------------
11v = 77
Divide both sides by 11.
v = 7
Substitute 7 for v in the first original equation and solve for b.
13v + 2b = 211
13(7) + 2b = 211
91 + 2b = 211
Subtract 91 from both sides.
2b = 120
Divide both sides by 2.
b = 60
Answer:
13v + 2b = 211
4v + 4b = 268
#students each VAN can carry: 7
#students each BUS can carry: 60
