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3 years ago

The product of some number and 40 is 2600

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the second factor of a multiplication problem with only the answer and the first factor, divide the answer by the first factor.

$2600/40= 65.$

Therefore, 40 × 65 = 2600.

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ZanzabumX [31]

Answer: The answer will be 28

Step-by-step explanation:

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4 years ago

The graphs below are both absolute value functions. The equation of the redgraph is f(x) = |xl. Which of these is the equation o

grigory [225]

ANSWER

$\Rightarrow y=\frac{1}{2}|x|$

EXPLANATION

We want to find the absolute value function for the line in blue.

The general form of an absolute value function is:

$y=a|x-h|+k$

where (h, k) = vertex

From the line, the vertex of the graph in blue is:

$(0,0)$

To find a, we have to pick a point (x, y) on the line and input it into the general function.

Let us pick (2, 1).

Therefore, we have:

$\begin{gathered} 1=a|2-0|+0 \\ 1=a|2|=2a \\ \Rightarrow a=\frac{1}{2} \end{gathered}$

Therefore, the absolute value function is:

$\begin{gathered} y=\frac{1}{2}|x-0|+0 \\ \Rightarrow y=\frac{1}{2}|x| \end{gathered}$

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1 year ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

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