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xeze [42]
2 years ago
8

I need to know how to do this I forgot please help.

Mathematics
1 answer:
Damm [24]2 years ago
4 0

Answer:

20 units

Step-by-step explanation:

calculating volume of a rectangular prism is done by multiplying length x width x height. the prism is 5 units tall, 2 units wide, and 2 units long (or deep), so you multiply 5x2x2 to get twenty

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When asked to write the domain for the equation y= |x - 6| + 3, Mary wrote the Domain is y < 3. What mistake(s) did Mary make
castortr0y [4]

Answer:

Ok, the domain is the set of values that we can input in a function.

In this case, we have:

y = Ix - 6I + 3.

Notice that there is no restriction here, x can actually take any value, then the domain will be the set of all real numbers.

The correct domain is x, x ∈ R

Now, if we had (for example) something like:

y = Ix - 6I < 3

Now we have a restriction in the domain because we can not have y equal or larger than 3.

To find the domain, we can break the absolute value:

Ix - 6I < 3

is equivalent to:

-3 < x - 6 < 3

now let's add 6 in each side.

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That will be the domain in that case.

6 0
2 years ago
What are the dimensions of the base of the pyramid?
aleksley [76]

Answer:

C

Step-by-step explanation:

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4 0
3 years ago
Simplify √9 x 3√27 please answer
irakobra [83]

Answer:

I got 27\sqrt{3} which is 46.76537.... in decimal form.

Step-by-step explanation:

4 0
3 years ago
Fifty multiplied by the quantity twenty divided by a number n is greater than or equal to two hundred fifty
Fudgin [204]
4 is the correct answer
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<em>To</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>polynomial</em><em>,</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>term</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>whole</em><em> </em><em>number</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

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