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Eduardwww [97]
3 years ago
10

Find FL if H is the circumcenter of EFG,

Mathematics
1 answer:
Zanzabum3 years ago
8 0

The artistic crop isn't helpful; it cuts off some vertex names.

The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn.  We have right triangle ELH, right angle L, so

EH² = HL² + EL²

EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339

Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.

Answer: 4.25

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Find the length of each side of the polygon for the given perimeter. p=54 mi
mote1985 [20]
This all depends upon the number of sides your polygon has.  I am assuming it is regular and that all the sides have the same length. If this is true, then the polygon will only be able to have the number of sides that is a factor of 54.  If this is a 27-gon, then each side will measure 2 mi; if this is an 18-gon, then each side will measure 3 mi; is this is a triangle, then each side will measure 18 mi; if this is a hexagon, then each side will measure 9 mi; if this is a 9-gon, then each side will measure 6 mi.  It all depends upon the number of sides you have.  Your answer will be found in the info above, again, assuming this is a regular polygon.
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3 years ago
NEED HELP!!! WILL MARK BRAINLIEST!!!
Tanzania [10]

Answer:

RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)

(x-11/2)/(x-4)

Step-by-step explanation:

Ok we need to simplify the expression so:

x^2+3x-10= Bhaskara formula=

-3(±√9-4·1·(-10))/2·1=

X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2

X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2

x^2-6x+8= Bhaskara formula=

6(±√36-4·1·8)/2·1=

X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2

X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4

so, The simplify expression is

(x-2)·(x-11/2)/(x-2)(x-4)=

8 0
3 years ago
Please help!!!
baherus [9]

Answer:

\huge  \colorbox{red}{  \rm (3x - 7)(x + 1)}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • PEMDAS
<h3>tips and formulas:</h3>
  • quadratic expression:ax²+bx+c

factoring quadratic:

  1. Find two numbers that multiply to give ac, and add to give b
  2. rewrite the middle with those numbers
  3. factor out common terms
  4. group
<h3>let's solve:</h3>

a is 3 and b is -7

\quad ac=3\times -7

therefore

\quad ac=-21

now we need to find two numbers that give -21

to do so we need to find the factors of 21

which are

\quad 1,3,7

likewise,

\quad -1,-3,-7

in this case we can take any two numbers from negative and positive factors that give us -21 and -4

3 and -7 are the two numbers that multiply to give -21 (3×-7=-21) and add to give -4. (3+(-7)=-4)

now let's factor:

  1. \sf rewrite \:  - 4x \: as \: 3x - 7x :  \\  \rm  {3 x}^{2} + 3x - 7x - 7
  2. \sf factor \: out \: 3x :  \\  \rm 3x(x + 1) - 7x - 7
  3. \sf factor \: out \:  - 7 :  \\  \rm 3x(x + 1) - 7(x + 1)
  4. \sf \quad group :  \\ \quad  \rm (3x - 7)(x + 1)

\text{And we are done!}

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3 years ago
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Which is equivalent to a+(-a)
Nikolay [14]

Answer:

Step-by-step explanation:

a+(-a)

=a-a

=0

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How much will 25 pounds of bananas cost if they are $0.59/pound
Nadusha1986 [10]
If you times 25 by .59 you'll get 14.75 so that is probs the answer
5 0
4 years ago
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