This all depends upon the number of sides your polygon has. I am assuming it is regular and that all the sides have the same length. If this is true, then the polygon will only be able to have the number of sides that is a factor of 54. If this is a 27-gon, then each side will measure 2 mi; if this is an 18-gon, then each side will measure 3 mi; is this is a triangle, then each side will measure 18 mi; if this is a hexagon, then each side will measure 9 mi; if this is a 9-gon, then each side will measure 6 mi. It all depends upon the number of sides you have. Your answer will be found in the info above, again, assuming this is a regular polygon.
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
Answer:

Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
- quadratic expression:ax²+bx+c
factoring quadratic:
- Find two numbers that multiply to give ac, and add to give b
- rewrite the middle with those numbers
- factor out common terms
- group
<h3>let's solve:</h3>
a is 3 and b is -7

therefore

now we need to find two numbers that give -21
to do so we need to find the factors of 21
which are

likewise,

in this case we can take any two numbers from negative and positive factors that give us -21 and -4
3 and -7 are the two numbers that multiply to give -21 (3×-7=-21) and add to give -4. (3+(-7)=-4)
now let's factor:





Answer:
Step-by-step explanation:
a+(-a)
=a-a
=0
If you times 25 by .59 you'll get 14.75 so that is probs the answer