Find FL if H is the circumcenter of EFG,
1 answer:
The artistic crop isn't helpful; it cuts off some vertex names.
The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so
EH² = HL² + EL²
EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339
Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.
Answer: 4.25
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The dimension of one side of the stamp was 2 centimeters
Step-by-step explanation:
The formula of the area of any square is A = l², where l is the
length of the side of the square
lance bought a square postage stamp to a mail a card to his cousin
∵ The stamp has 4 square centimeters
∴ The area of the stamp = 4 cm²
∵ The stamp shaped a square
∵ The formula of the area of the square is A = l²
- Equate the formula of the area of the square by the area of the stamp
∴ l² = 4
- Take √ for both sides to find l
∴
∴ l = 2 cm
The dimension of one side of the stamp was 2 centimeters
Learn more:
You can learn more about the area of the shapes in brainly.com/question/10677255
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