Find FL if H is the circumcenter of EFG,
1 answer:
The artistic crop isn't helpful; it cuts off some vertex names.
The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so
EH² = HL² + EL²
EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339
Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.
Answer: 4.25
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Step-by-step explanation:
To find the vertical asymptote(s) of a rational function,
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Learn more:
You can learn more about the asymptotes in brainly.com/question/6459599
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Answer:
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Step-by-step explanation:
<u><em>The correct quadratic equation is</em></u>
2x^2+11x+15=0
we know that
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