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hram777 [196]
3 years ago
12

Please help me 1 through 9

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

1) the angles are congruent, or the same

2) the angles are complementary, or add up to 90 degrees

3) the angles add up to 180 degrees

4) the angle is a right angle

5) they are congruent

6) they are complementary angles, or add up to 90 degrees

7) they are supplementary angles, or add up to 180 degrees

8) angle 1 is congruent to angle 4

9) angle K is supplementary to angle L

Step-by-step explanation:

8 and 9 are transitivity

The other statements correspond with the sentence starters.

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the sum of the 10th and 11th terms of an arithmetic sequence is 65 what is the sum of its first 20th terms​
Dmitriy789 [7]

Answer:

this is the answer

Step-by-step explanation:

a 65

b 650

c 52

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6 0
2 years ago
8x - 8 - x = 3 (6 - 2x)
Ksivusya [100]

Answer:

x = 2

Step-by-step explanation:

8

−

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{\color{#c92786}{8x}}-8{\color{#c92786}{-x}}=3(6-2x)

8x−8−x=3(6−2x)

7

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7 0
2 years ago
I am the largest 7-digit number you can write with the digits 3, 6, 9, 4, 0, 8, and 2
nirvana33 [79]
9,864,320

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5 0
3 years ago
Read 2 more answers
Simplify.<br><br> (-7p)3<br><br> please help
OleMash [197]

Answer:

-343p^3

Step-by-step explanation:

This is the answer because -7x-7x-7 would be -343 and you MUST keep the negative sign. The p x pxp would be p^3

Multiply the numbers:

-343p^3 would be your answer

Hope this helps!! :D

8 0
3 years ago
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What is the equation of a line that is perpendicular to the x-axis and passes through (3,-2)
34kurt

Answer:

x = 3

Step-by-step explanation:

we know that if we have an original line and we are finding the perpendicular we know that the slope of the second line is gonna be the negative reciprocal of the first line and given that we know it must be  perpendicular to the original line it will be heading downwards on the y axis with no slope so instead of y equals it will be x equals and we know that our x value of the point given is three so the answer is x = 3

4 0
3 years ago
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