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TEA [102]
2 years ago
10

P(x)= 4x^3 -3x^2+5x-2​

Mathematics
1 answer:
PIT_PIT [208]2 years ago
6 0

Answer:

p=4x^3−3x^2+5x−2/x

Step-by-step explanation:

Let's solve for p.

px=4x^3−3x^2+5x−2

Step 1: Divide both sides by x.

px/x=4x^3−3x^2+5x−2/x

p=4x^3−3x^2+5x−2/x

Answer:

p=4x^3−3x^2+5x−2/x

( I hope this was helpful) >;D

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I believe it is C hope it helps
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3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
Find the slope of the line that contains the two points (0,1) and (1,3)
klio [65]

Answer:

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Step-by-step explanation:

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plug in 3 for y2 and 1 for y1

plug in 1 for x2 and 0 for x1

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_______________

for y=mx+b *extra info ig if u need it just incase*

i usually use the first point for this but u can use any one u want

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subtract o on both sides

1=b and b is ur y-intercept

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hope this helps

7 0
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56/8 = 7
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sleet_krkn [62]
Make an equation where

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The graph of that equation is guaranteed to be a parabola.
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