Answer:

Step-by-step explanation:


over 3

For y=x^2-6x-11
complete the square
so roots
set y=0
0=x^2-6x-11
group x terms
0=(x^2-6x)-11
take 1/2 of linear coefient (-6) and square it
-6/2=-3, (-3)^2=9
add positive and neative to inside of parenthasees
0=(x^2-6x+9-9)-11
complete square
0=((x-3)^2-9)-11
expand
0=(x-3)^2-9-11
0=(x-3)^2-20
add 20 to both sides
20=(x-3)^2
sqrt both sides
remember positive and negative roots
+/-2√5=x-3
add 3 to both sides
3+/-2√5=x
so
x=3+2√5 and 3-2√5
Hi there! :)
Answer:

To find the area of the shaded region, we will need to find the areas of both the rectangle and the circle:
Rectangle: A = l × w
A = 11 × 12
A = 132 cm²
Circle: A = πr² (Let π = 3.14)
A = π(2)²
A = 4π
A ≈12.56 cm²
Subtract the area of the circle from the area of the rectangle:
132 - 12.56 = 119.44 cm².
Answer:
the answer is Monomial I hope this helps
Answer:
1x1
Step-by-step explanation: