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Anuta_ua [19.1K]
3 years ago
13

Compare the values of 700 and 70

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
700 is 10 times bigger than 70
Vladimir [108]3 years ago
5 0
Well 700 is ten times bigger than 70 70 x 10 = 700
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Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee
solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

base (b) = 3cm, height (h) = 9cm

Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2

Dimensions of the small ∆:

base (b) = 2cm, height (h) = 6cm

Area = 0.5*b*h = 0.5*2*6 = 6 cm^2

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

5 0
3 years ago
Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u
olga nikolaevna [1]

Answer:

Sample response:

Step-by-step explanation:

She would multiply the rate by the years to find the average rise in water levels, or 1.8 times 6.2 = 11.16. To find the difference between the water levels, she would subtract -13.64 from 11.16.

7 0
3 years ago
Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the
nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

A = 6 * 81

A = 486 inches^2

3 0
3 years ago
What is the value of x? show work
Alona [7]
2x+38=180
2x=142 (or x+x=142 from which 2x=142)
x=71 

The unknown angles are each 71

You know this answer is logical as, since two sides are 21 it hints that we are looking at an equilateral triangle, which means two of its angles will be the same
7 0
3 years ago
If f(x)=ln(sin(2x)), f''(π/4) is equal to​
Licemer1 [7]

Use the chain rule to compute the second derivative:

f(x)=\ln(\sin(2x))

The first derivative is

f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}

f'(x)=2\cot(2x)

Then the second derivative is

f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'

f''(x)=-4\csc^2(2x)

Then plug in π/4 for <em>x</em> :

f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4

4 0
3 years ago
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