Answer:
The approximate length of the diagonal walkway is 21.21 meters
Step-by-step explanation:
we know that
Applying the Pythagorean Theorem in the square park, find out the the approximate length of the diagonal walkway
so
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
where
c is the diagonal of the square
a and b are the length sides of the square
we have
![a=15\ m\\b=15\ m](https://tex.z-dn.net/?f=a%3D15%5C%20m%5C%5Cb%3D15%5C%20m)
substitute
![c^2=15^2+15^2\\c^2=450\\c=21.21\ m](https://tex.z-dn.net/?f=c%5E2%3D15%5E2%2B15%5E2%5C%5Cc%5E2%3D450%5C%5Cc%3D21.21%5C%20m)
therefore
The approximate length of the diagonal walkway is 21.21 meters
Answer:
are we supposed to multiply
Step-by-step explanation:
Step-by-step explanation:
since it is in the same line as DE, both have the same slope.
the slope is the ratio of "y coordinate change / x coordinate change" when going from one point on the line to another.
and so by using the coordinates of D and E
x changes by +4 (from 8 to 12).
y changes by -8 (from 32 to 24).
the slope is therefore
-8/+4 = -2
Pythagorean theorem is a^2 + b^2 = c^2
2. You are trying to find x which is c^2
so plug in the other numbers to the other letters. 9^2 + 17^2 = c^2
9^2= 81. 17^2= 289
81 + 289 = 370
370= c^2
Now all you have to do is square root the number
*square root sign* 370
19.24
c = 19.24
So, x = 19.24