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katrin2010 [14]
2 years ago
8

How do you write 20 in exponential form

Mathematics
1 answer:
seropon [69]2 years ago
6 0

Answer:

2 to the power of 2 times 5 to the power of 1

= 20

Step-by-step explanation:

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Find three consecutive positive integers such that the product of the first and​ third, minus the​ second, is 1 more than 7 time
Bas_tet [7]
--------------------------------------------------------------------
Define x :
--------------------------------------------------------------------
Let the smallest number be x.
First number = x
Second Number = x + 1
Third Number = x + 2

--------------------------------------------------------------------
Construct equation :
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x(x+2) - (x+1) = 7(x+2) + 1

--------------------------------------------------------------------
Solve x :
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x(x + 2) - (x + 1) = 7(x + 2) + 1
x² + 2x - x - 1 = 7x + 14 + 1
x²- 6x - 16 = 0
<span>(x+2)(x-8) = 0
</span>x = -2 or x = 8

Since x is a positive integer, it cannot be negative.
⇒x = 8

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Answer: The three numbers are 8, 9 and 10.
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2 years ago
$8 buys 40 ounces of ground turkey
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Bethany is 62 in tall Bethany's brother scott is 3 inches taller than her she is write Scott's height in feet and inches
MrRissso [65]
Scott is 62+3=65 inches tall, and there are 12 inches in a foot, so you get 65/12=about 5 whole feet. 5 whole feet is 60 inches in total, so we have a leftover 5 inches, meaning that Scott is 5 feet and 5 inches tall.
8 0
2 years ago
The equation __ describes the relationship
vivado [14]

Answer:

y= 1/3x

Step-by-step explanation:

points on the graph

(0,0), (3,1)

function as per above two points:

y= 1/3x

5 0
3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
2 years ago
Read 2 more answers
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