2 years ago

The equation of the line is y =?

Mathematics

1 answer:

vredina [299]2 years ago

3 0

Answer:

y = -x/2 - 14

Step-by-step explanation:

Hint: The slope shows the rise over run, in this case, the slope is going 1 unit to the right and two units down.

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R^2+8r=-7<br>solve the equation with the quadratic formula showing work

Yuliya22 [10]

Answer:

Step-by-step explanation:

r²+8r=−7

Step 1: Subtract -7 from both sides.

r²+8r−(−7)=−7−(−7)

r²+8r+7=0

Step 2: Use quadratic formula with a=1, b=8, c=7.

r= $r=\frac{-b+or-\sqrt{-4ac} }{2a}$

$r=\frac{-8+or-\sqrt{(8})^2-4(1)(7) }{2(1)}$

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3 years ago

Which expression is equivalent ?<br><br> LOOK AT THE PICTURE

victus00 [196]

Answer:

x^ (5/3) y ^ 1/3

Step-by-step explanation:

Rewriting as exponents

(x^5y) ^ 1/3

We know that a^ b^c = a^(b*c)

x^ (5/3) y ^ 1/3

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3 years ago

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Two angles are complementary. The measure of ∠ABC is x° and the measure of ∠DBC is (3x + 10)°. What is the value of x?

beks73 [17]

42.5 I think

3x+10+x=180
4x=170
170/4=x
X=42.5

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2 years ago

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Given sec(theta)= 5... find cot(90-theta)

Mumz [18]

$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 } = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6} 
\\
$

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2 years ago

What’s the answer to this problem that I can not figure out

Maslowich

Answer:

-64/3 HOPE THIS HELPS if you need more help let me know

4 0

2 years ago