So, to set up your equation is the hardest part. If you remember the basic format, you're set.
I(t) = P * (1+r%)^t
t= time and this will be our variable
Initial amount P = $2740
Rate = 4.3% which converts numerically into .043
I(t) = 7000
Before we get to find out how to find how many years it takes to get to $7000, set up the basic equation by plugging in what we know.
I(t) = $2740(1+4.3%)^t
I(t)=2740(1.043)^t
Now plug in for $7000 for I(t)
7000=2740(1.043)^t Divide both sides by 2740
7000/2740 = 2740/2740(1.043)^t
2.55474453=(1.043)^t
Now you can solve for t in two ways. You can either use the natural log or graph it on your graphing calculate and see when the two equations meet.
In your calculator you can set up:
ln(2.55474453)/ln(1.043) = t which is the method I prefer since it's much simpler
t=22.278528
but you can also graph it in your ti-84
with
y1=2.55474453
y2=(1.043)^x
and find where they intersect on the graph.
either way it'll be the same answer
Answer:
Step-by-step explanation:
Set up the equation:
Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:
20t^2 = 15000
t^2 = 750
t = 
The year will be simply 1998 + 5 \sqrt{30}
Answer:
A, dilation by a scale factor of 2 and a reflection across the y-axis
Step-by-step explanation:
Answer:
He would have to wait for 5 weeks
Step-by-step explanation:
$5 x $5 = $25
$25 + $10.50 = $35.50
