3 years ago

M<2=3x-28 and m<4=2x-10 find m<1

Mathematics

1 answer:

kirill115 [55]3 years ago

7 0

637

hope that helped :)))

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The family of functions y = ce^{-2x} + e^{-x} is solution of the equation y' + 2y = e^{-x}. Find the constant c which defines th

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Answer:

$c = 1190.2$

Step-by-step explanation:

We have the following solution:

$y(x) = ce^{-2x} + e^{-x}$

We want to find the value of x that satisfies the following condition:

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This means that when x = 3, y = 3. So

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$3 = ce^{-6} + e^{-3}$

$3 = ce^{-6} + 0.0498$

$ce^{-6} = 2.9502$

$c = \frac{2.9502}{e^{-6}}$

$c = 1190.2$

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