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jeyben [28]
3 years ago
15

Which can more efficiently supply nutrients and

Biology
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

Smaller Cells

Explanation:

Basically, small cells have larger surface area but smaller volume, its vice versa for larger cells.

Not to forget that the functions of a cell are related to the diffusion, osmosis and active transport movement.

Factors to consider for a faster diffusion/ osmotic movement includes:

Surface Area

Size of molecule

Difference in concentration gradient

Temperature

Distance

So as per the factors, when there is a larger surface area, the rate diffusion/ osmosis increases hence increasing its efficiency.

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Answer:

False

Explanation:

Hope this helps!

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3 years ago
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Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide
seropon [69]

0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.

<h3>What are monosaccharides?</h3>

Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.

There are two types of monosaccharides;

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  • ketose sugars e.g. fructose.

When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.

Considering the give question:

Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.

The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:

1 disaccharide molecule contains 2 monosaccharide molecules

0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.

0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules

0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.

Learn more about monosaccharides and disaccharides at: brainly.com/question/731310

#SPJ1

7 0
1 year ago
relay runner is running 1 m/s and reaches 5m/s when given the baton after 3 sec. What is the acceleration? (Make sure you do the
Len [333]

Answer:

4/3 m.s2 forward

Explanation:

final velocity minus initial velocity. divide all of that by 3 seconds

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