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swat32
3 years ago
14

Without solving explain why the equations do not have solutions​

Mathematics
1 answer:
Talja [164]3 years ago
5 0
<h2>Examining the equation</h2>

We have 2 terms:

\sqrt{x+2} and \sqrt{4x+1}

For the sum of these to equal a negative number, in this case -3, one of these terms would have to be negative.

<h2>So what's the problem?</h2>

The function \sqrt{x} (square root of x) only returns positive values!

(See the attached image for a graph of \sqrt{x})

Since neither of the terms can be negative, it can't be equal to -3. In other words, no matter what we put as x, we can't solve the solution, so we say that the equation <em>does not have any solutions.</em>

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How many solutions exist for the given equation?
trasher [3.6K]

Answer:

  • Infinitely many solutions

Step-by-step explanation:

  • 3(x + 10) + 6 = 3(x + 12)
  • 3x + 30 + 6 = 3x + 36
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6 0
3 years ago
I am confused in this can someone help?
fgiga [73]

Answer:

\huge\boxed{\sf a = -12 , b = 8}

Step-by-step explanation:

<u>Given polynomial is:</u>

f(x) = ax^3+ b^2 + 3x + 4

\rule[225]{225}{2}

First factor is (x-1)

Let x - 1 = 0  => x = 1

Putting this in the above polynomial

f(1) = a(1)^3 + b(1)^2 + 3(1) + 4

Given that it's remainder is 3

3 = a + b + 3 + 4

3 = a + b + 7

Subtracting 7 to both sides

-4 = a + b\\OR \\

<h2>a + b = -4 -------------------------- (1)</h2>

\rule[225]{225}{2}

Second Factor is 2x + 1

Let 2x + 1 = 0 => x = - 1 / 2

Putting in the above polynomial

f(-\frac{1}{2} ) = a (-\frac{1}{2} )^3 + b (-\frac{1}{2} )^2  + 3 (-\frac{1}{2} ) + 4

The remainder is 6

6 = -\frac{a}{8} + \frac{b}{4} - \frac{3}{2} + 4\\6 - 4 = -\frac{a}{8} + \frac{b}{4} - \frac{3}{2}\\2 = \frac{-a + 2b -12 }{8} \\-a + 2b - 12 = 16\\-a + 2b = 16 + 12\\

<h2>-a + 2b = 28  --------------------------------(2)</h2>

\rule[225]{225}{2}

Adding both equations

a + b -  a + 2b = -4 + 28

3b = 24

Dividing both sides by 3

b = 8

\rule[225]{225}{2}

Putting b = 8 in Equation (1)

a + 8 = -4

a = - 4 - 8

a = -12

\rule[225]{225}{2}

8 0
4 years ago
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