notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.
![\bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cbegin%7Barray%7D%7Bcccll%7D%5Cstackrel%7Bx%7D%7Bn%7D%26term%26%5Cstackrel%7By%7D%7Bvalue%7D%5C%5C%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C1%26a_1%26-10%5C%5C%5C%5C2%26a_2%26%5Cstackrel%7B-10%2B3%7D%7B-7%7D%5C%5C%5C%5C3%26a_3%26%5Cstackrel%7B-7%2B3%7D%7B-4%7D%5C%5C%5C%5C4%26a_4%26%5Cstackrel%7B-4%2B3%7D%7B-1%7D%5C%5C%5C%5C5%26a_5%26%5Cstackrel%7B-1%2B3%7D%7B2%7D%5C%5C%5C%5C6%26a_6%26%5Cstackrel%7B2%2B3%7D%7B5%7D%5Cend%7Barray%7D%20)
check the picture below.
It is 46 if you divide 34 by 16 you get 2.125 then divide 100 by 2.125 and you get 47.05 the 0 means go down if you are rounding which brings it to 46
5x-1= 26
5x-1+1= 26+1
5x= 27
Divide by 5 for 5x and 27
5x/5= 27/5
x= 27/5
Answer is x= 27/5 - A)
Answer:
C.It is a one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.
Step-by-step explanation:
Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:
: p=10%
: p>10%
The alternative hypothesis states that the parameter is greater than the hypothesized value.
4.5 x 4.5 = 20.25 x 4.5 = 91.125 in