Answer:
C= 38 in Approx
A=113 in^2 Aprprox
Step-by-step explanation:
Given data
radius= 6 ft
Circumference, C=2πr
substitute
C=2*3.142*6
C=37.704 in
Area A= πr^2
substitute
A=3.142*6^2
A=3.142*36
A=113.112 in^2
Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
The calculator returns an error as the answer for the inverse sine of 1.055 because the acceptable range for sine is only from 0 to 1.00 in which 1.055 is clearly greater than. This is also the same as for the cosine values.
Answer:
Step-by-step explanation:
Hello!
(5x+4) /( (x-4)( x+2))
(5x+4)/ (x² +2x -4x -8)=
(5x+4) /( x²-2x -8)