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juin [17]
3 years ago
10

Can someone help me with this?

Mathematics
2 answers:
antoniya [11.8K]3 years ago
6 0
I’m not sure. sorry sir
Readme [11.4K]3 years ago
5 0
I have question that too but quadratic equations
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Linda
Nataliya [291]

Answer: 6

Step-by-step explanation:

The circumference is always x2 of the radius

4 0
4 years ago
In the 30-60-90 triangle below, side s has a length of and the hypotenuse has a length of
Zepler [3.9K]
Are there any dimensions on the triangle? or is it in terms of s? if so the answer would be 2s/sqrt(3) or you can rationalize the bottom and youd get 2sqrt(3)s/3
6 0
3 years ago
Read 2 more answers
What is the equation of this line?<br><br> y=3x−2<br><br> y=13x−2<br><br> y=2x−3<br><br> y=12x−3
bekas [8.4K]

Answer is A. y=3x−2 (i took the quiz on k12 and this was the correct answer so it may be different depending on your school)

7 0
3 years ago
A shirt cost $18.99 with a 6.5% sales tax. What is the final cost?
velikii [3]

Answer:

$20.22

Step-by-step explanation:

You multiply 18.99 with 0.065 to see how much extra money you have to pay. Then you add it back to 18.99 for the final cost.    

3 0
3 years ago
WILL GIVE BRAINLIEST, 5/5 RATING, AND FAVORITE.
CaHeK987 [17]

Answer:

y = -\frac{1}{2}x + 2

Step-by-step explanation:

Assume this is function is a straight line, consider the equation of the straight line: y=mx + c

To find the gradient of the equation, we use any two coordinates from the table. (x_1,y_1) = (6,-1)\\(x_2,y_2) =(2,1)

m = \frac{y_1 - y_2}{x_1 - x_2}\\\\m = \frac{1-(-1)}{2-6}\\\\m=\frac{2}{-4} \\\\m=- \frac{1}{2}

We substitute the value of m in the equation:

y =mx+c\\y = - \frac{1}{2} x + c\\\\

To find c, we use the leftover coordinates, (4,0) in the equation above:

y = -\frac{1}{2}x+c\\\\0 = -\frac{1}{2} \times 4+c\\\\0 = -2 + c\\\\c=2\\\\

Substitute this value of c in the equation to get the function:

y = -\frac{1}{2}x + 2

4 0
3 years ago
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