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zvonat [6]
3 years ago
7

We can use the formula density mass over volume to find the density of a substance square metal plate has a density of 10.7 g of

per cubic centimeters and a mass of 23.54 g calculate the volume
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer: The volume of given substance is 2.2 cm^{3}.

Step-by-step explanation:

Given: Density = 10.7 g/cm^{3}

Mass = 23.54 g

Density of a substance is the mass of substance divided by its volume.

Mathematically, Density = \frac{mass}{volume}

Substitute the values into above formula to calculate volume as follows.

Density = \frac{mass}{volume}\\10.7 g/cm^{3} = \frac{23.54 g}{volume}\\volume = \frac{23.54 g}{10.7 g/cm^{3}}\\= 2.2 cm^{3}

Thus, we can conclude that the volume of given substance is 2.2 cm^{3}.

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Answer:

Step-by-step explanation:

Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calculate the average rate of change for the entire trip.

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3 years ago
A high rise building has a sink on the fourth floor located 2-feet above the floor. Each floor is 10-feet above the other. Calcu
kap26 [50]
The pressure at a certain height is the pressure at sea level plus the hydrostatic pressure.

P = 80 psi + ΔP
where
ΔP = ρgh
ρ is the density of water equal to 62.4 lbm/ft³
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4 years ago
Find the equation of the line with a slope of 12 that passes through the point (3, -1)
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Answer:

y = 12x - 37

Step-by-step explanation:

The equation of a line in slope- intercept form is

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here m = 12, thus

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4 years ago
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Which scenarios involves right triangles?
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c

Step-by-step explanation:

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3 years ago
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When drawn in standard position, an angle a has a terminal ray that lies in the second quadrant and whose sine is equal to 9/41.
Semenov [28]

Answer:

\frac{40}{41}

Step-by-step explanation:

We have the angle in standard post has a sine ratio of

\frac{9}{41}

This means the opposite side length of the corresponding right triangle is 9 units and the hypotenuse is 41 units.

Using Pythagoras Theorem, the adjacent side length can be found using:

{x}^{2}  +  {9}^{2}  =  {41}^{2}

This implies that:

{x}^{2}  =  {41}^{2}  -  {9}^{2}

{x}^{2}  =  1600

x =  \pm \sqrt{1600}

x =  \pm40

The cosine ratio is adjacent over hypotenuse.

=  \frac{ \pm40}{41}

Since we are in the second quadrant, the cosine ratio is negative;

=  -  \frac{40}{41}

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