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krek1111 [17]
4 years ago
10

What is the product of (-4x2-5x-1)(4x2-6x-2)

Mathematics
1 answer:
Stells [14]4 years ago
7 0
(-4x2-5x-1)(4x2-6x-2)

Final result :

-2 • (13x + 1) • (2x2 - 3x - 1)
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(-13x - 1) • ((22x2 - 6x) - 2)
Step 2 :

Pulling out like terms :

3.1 Pull out like factors :

-13x - 1 = -1 • (13x + 1)

Step 3 :

Pulling out like terms :

4.1 Pull out like factors :

(4x2 - 6x - 2) = 2 • (2x2 - 3x - 1)

Trying to factor by splitting the middle term

4.2 Factoring 2x2 - 3x - 1

The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2

Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -3 .

-2 + 1 = -1
-1 + 2 = 1

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Step 4 :

Pulling out like terms :

5.1 Pull out like factors :

-26x - 2 = -2 • (13x + 1)

Final result :

-2 • (13x + 1) • (2x2 - 3x - 1)
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a) 0.5.

b) 0.8413

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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This is 1 subtracted by the pvalue of Z when X = 6. So

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Z = \frac{6-6}{0.2}

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(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

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Z = \frac{6.2-6}{0.2}

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(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

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This is 1 subtracted by the pvalue of Z when X = 5.7.

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Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

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1 - 0 = 1

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