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2 years ago

8.

Mathematics

2 answers:

nlexa [21]2 years ago

4 0

Answer:

B. 5x2 + 7x – 26

Step-by-step explanation: keeping in mind that the area of a rectangle is simply width * length, if we get the area of the larger rectangle, and then subtract the area of the smaller rectangle, we're in effect making a hole in the larger rectangle's area and thus what's leftover is the shaded area.

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Answer:

Area = 5x^2 +7x -26

Step-by-step explanation:

The area of the shaded region can be found if you substruct the small rectangle from the big one. The area of any rectangle is calculated if you multiply width and height.

In other words:

A_small = (x-3)(x-6) = x^2-9x +18

A_big = (2x+2)(3x-4) = 6x^2 -2x -8

A_big - A_small = (6x^2 -2x -8) - (x^2-9x +18)

= 6x^2 -2x -8 - x^2 + 9x -18

= 5x^2 +7x -26

Tpy6a [65]2 years ago

3 0

Area of the shaded region = area of big square minus area of little square.

Here is the set up:

Let A_s = area of shaded region.

A_s = (2x + 2)(3x - 4) - [(x - 3)(x - 6)]

Take it from here.

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Please help I need answers #5 and #6 more, but if you could do all that would be great thanks it’s urgent!!!

Rudiy27

Answer:

Step-by-step explanation:

Answer for #5

Two Points M(-7,1) and N(5,1).

1. Formula is $Distance = \sqrt{(x2-x1)^2 - (y2-y1)^2}$

2. Let’s say (x1,y1) = (-7,1) and (x2,y2) =(5,1)

3. Distance = $\sqrt{(5-(-7))^2 + (1-1)^2} = \sqrt{(5+7)^2-(0)^2} = \sqrt{(12)^2+0} =\sqrt{144} = 12}$

so distance between two warehouses is 12 miles

Answer #6

In the question it is saying the “Distance between two stores is half the distance between warehouses“ so it is $\frac{12}{2}$ = 6 miles

Answer #7

S1(-4,1) and distance of S1 and M is 3 Miles.

Answer #8

S2(2,1) and distance of S2 and M is 3 miles.

4 0

3 years ago

let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is

svlad2 [7]

Answer:

The value of q and p is 4 and -24 respectively.

Step-by-step explanation:

Being $f(x)=\frac{p+8}{x-q}$ , the line x=4 is a vertical asymptote to the graph of f(x). The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

x - q= 0

Solving:

x= q

Being the line x=4 the vertical asymptote, then

4=q

Then the function f (x) is:

$f(x)=y=\frac{p+8}{x-4}$

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

$4=\frac{p+8}{0-4}$

Solving:

$4=\frac{p+8}{-4}$

4*(-4)= p+8

-16= p+8

-16 - 8= p

-24= p

The value of q and p is 4 and -24 respectively.

7 0

3 years ago

Solve each equation by factoring x^2+4x+4=0

makkiz [27]

Answer: x = -2

Step-by-step explanation:

Find 2 numbers whose product is the c-value of 4 and their sum is the b-value of 4.

x² + 4x + 4 = 0

∧

1 + 4 = 5

2 + 2 = 4 this works! so the factors are:

(x + 2)(x + 2) = 0

x + 2 = 0 and x + 2 = 0

x = -2 and x = -2 --> same answer so only need to list it once

6 0

3 years ago

Given :f(x) =1/x+5 and g(x) =x-2 What are the restrictions of the domain of f(g(x))?

emmainna [20.7K]

I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7

5 0

3 years ago

Read 2 more answers

NEED THIS DONE ASAP!! Thank you!!

g100num [7]

Answer:

$\overset{\frown}{WX}= 66^{\circ}$