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Lena [83]
3 years ago
9

Question 1 of 5

Mathematics
2 answers:
GenaCL600 [577]3 years ago
3 0

Answer:

A because if you multiply 12x6 = 72

kondaur [170]3 years ago
3 0

Answer:

The correct answer is 72 pi m*3

Step-by-step explanation:

Ap3x

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M is the midpoint of AB. find the coordinates of B if M= (-1,1) and A= (2,6)
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The other coordinate B is = (-4,-4)
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Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.
Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that n = 20, \pi = \frac{8}{20} = 0.4.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

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4 years ago
Scientific Notation.
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400Million meteres tall

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Stephen has art lesson every 6 days.And a swim lesson every 9 days.He has both art and swim lesson on Tuesday.On which day of th
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Yes.

Step-by-step explanation:

The polygons are similar

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