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3 years ago

1/2 mi = 880 yd O True O False Help

Mathematics

2 answers:

Ksivusya [100]3 years ago

6 0

Answer:

True

Step-by-step explanation:

1,760 yds = 1 mile, 1,760 ÷ 2 = 880

Black_prince [1.1K]3 years ago

5 0

I don’t know I am just guessing but it’s False good luck

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(4x + 8x - 5) + (3x2 + 6x - 7)

ch4aika [34]

Answer:

7x^2 + 14x - 12

Step-by-step explanation:

Add like terms:

(4x + 8x - 5) + (3x2 + 6x - 7) becomes:

4x^2 + 8x - 5 or (grouping like terms in columns):

+ 3x^2 + 6x - 7

---------------------

7x^2 + 14x - 12

5 0

3 years ago

The cost of 4 pounds of grapes is $24.36.wgat is the constant of proportionality

IRINA_888 [86]

The answer
A:6.09

Th explanation
Divide 24.36 by 4 and that’s what you get

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3 years ago

A person is trapped in a burning building 60feet off the ground. A rescuer has a 70 foot ladder, but for safety purposes the lad

Neko [114]

Yes because, if the building is 60 ft from the ground and the ladder is 70 ft,shouldn’t it escalate an extra 10 ft because this is technically an emergency and it can be considered to be used as a reason for safety purposes, if I’m not mistaken

3 0

3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago

What is the volume of a sphere with a diameter of 15 cm? Round the answer to the nearest whole number.

AveGali [126]

Answer:

1767 cm³

Step-by-step explanation:

We can use volume V = 4/3 π r³

We have diameter of 15 cm. To get radius, we need to divide diameter by 2.

r = 7.5 cm

So now plug in r = 7.5 then calculate V:

V = 4/3 π ( 7.5 )³

V = 4/3 π * 421.875 ≈ 1767.145 ≈ 1767

Hope this helps.

8 0

3 years ago