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Nitella [24]
2 years ago
9

F

Mathematics
1 answer:
Burka [1]2 years ago
6 0

Answer:

12

Step-by-step explanation:

F \alpha \frac{1}{d^{2} }

F = \frac{K}{d^{2} }

When F = 18; d = 2

18 = \frac{K}{2^{2} }

18 = \frac{K}{4}

Cross multiply;

18 x 4 = K

72 = K

There the equation connecting F and d^{2} is

F = \frac{72}{d}

Now, Find F when d = 6

All you do is to substitute d = 6 in to F = \frac{72}{d}

F = \frac{72}{6}

Therefore;

F = 12

Please mark me brainiest if correct.

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How do you do recursive formulas
Norma-Jean [14]

Answer:

Determine if the sequence is arithmetic (Do you add, or subtract, the same amount from one term to the next?)

Find the common difference.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
One gram of water has a volume of 1 millimeter. What is the volume of the water if it has a mass of 1 kilogram
Zinaida [17]
There are 1,000 grams in a kilogram. 
Each gram of water has a volume of 1 milliliter (the question said millimeter but that measures length and I think it was meant to say milliliter). 
Since there are 1,000 grams with a volume of 1 millimeter each, the volume is 1,000 milliliters, which is equal to 1 liter. 
Hope this helps!

8 0
3 years ago
What is the probability that a marble chosen at random is
Brums [2.3K]

Answer:

P=\frac{6}{11}

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

P=\frac{6}{11}

The right answer is the last choice.

4 0
3 years ago
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Please answer this, I’m a bit confused...
tatuchka [14]

Answer: The distance across a rectangular field is longer distance.

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Diagonal of square would be 56.56 yards.

3 0
2 years ago
When the solutions are going to be complex, which methods can be used to solve quadratic equations?
yKpoI14uk [10]
You could complete the square to state the vertex. 
You could use the quadratic equation to find the roots (which are complex). 

Try an example that will require both.

y = x^2 + 2x + 5

Step One
Get the graph. That's included below.

Step Two
Provide the steps for completing the square.
Note: we should get (-1,4)

y= (x^2 +2x ) + 5
y = (x^2 +2x + 1) + 5 - 1
y = (x +1)^2 + 4

The vertex is at (-1,4)

Step Three
Find the roots. Use the quadratic equation. Note that the graph shows us that the equation never crosses or touches the x axis. The roots are complex.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 2
c = 5

\text{x = }\dfrac{ -2 \pm \sqrt{2^{2} - 4*1*5 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{4 - 20 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{-16 } }{2}
\text{x = }\dfrac{ -2 \pm 4i }{2}
x = -1 +/- 2i

x1 = -1 + 2i
x2 = -1 - 2i And we are done.


7 0
3 years ago
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