a soccer team hopes to win at least 3 games for every 2 lost during the season. if there are 15 games scheduled, how many games
can the team lose and still achieve its goal
1 answer:
Answer:
This team can lose 6 games and still achieve this goal.
Step-by-step explanation:
In order to find this, we can create a proportion and solve by cross multiplying. The proportion should compare amount of losses to total games.
Ratio = Total
2/5 = x/15
Now cross multiply
15*2 = 5x
30 = 5x
6 = x
This means the team can lose 6 games and still keep the necessary ratio.
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Answer:
No Solution.
Step-by-step explanation:
2x+3y=4
4x+6y=9
-------------
-2(2x+3y)=-2(4)
4x+6y=9
----------------------
-4x-6y=-8
4x+6y=9
-------------------
0=1
no solution
Multiply both sides by negative four to get rid of the fraction
j+18=-32
subtract 18
j=-50
Answer:
Step-by-step explanation:
Solving for brackets and multiplying.
Adding the numbers in the denominator.
Dividing.