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user100 [1]
3 years ago
11

a soccer team hopes to win at least 3 games for every 2 lost during the season. if there are 15 games scheduled, how many games

can the team lose and still achieve its goal
Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

This team can lose 6 games and still achieve this goal.

Step-by-step explanation:

In order to find this, we can create a proportion and solve by cross multiplying. The proportion should compare amount of losses to total games.

Ratio = Total  

2/5 = x/15

Now cross multiply

15*2 = 5x

30 = 5x

6 = x

This means the team can lose 6 games and still keep the necessary ratio.

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the equation d= 2/5 t describes the distance d, in yards, an object travels in t minutes. How long does it take the object to tr
uranmaximum [27]

Answer:

t = 4.5

Step-by-step explanation:

1.8 = 0.4(t) solve for t

4 0
3 years ago
Identify the area of the figure rounded to the nearest tenth. HELP?!! I don't understand!! Please help and show your work!!
Alex73 [517]

Answer:

67.5\ cm^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle (figure 1) plus the area of trapezoid (figure 2)

see the attached figure to better understand the problem

The area of the rectangle is

A=15*3=45\ cm^{2}

The area of the trapezoid is

A=\frac{1}{2}[(15-9)+3)](8-3)

A=\frac{1}{2}[6+3)](5)=22.5\ cm^{2}

The area of the figure is

45\ cm^{2}+22.5\ cm^{2}=67.5\ cm^{2}

8 0
3 years ago
Solve the following equation: <br><br> x^3 -168 = [24(x-2)] / 2<br><br> PLEASE REPLY ASAP
Nataly_w [17]
Hi Larry

x^3 - 168 = [ 24(x-2)] / 2
x^3 - 168 = (24x - 48)/2
x^3 - 168 = 12x - 24
Subtract 12x - 24 to both sides
x^3 - 168 - (12x - 24) = 12xx - 24 - (12x - 24)
x^3 - 12x - 144 = 0
Now, factor the left sides
(x - 6)(x^2 + 6x + 24) = 0
Set factors equal to 0
x - 6 = 0 or x^2 + 6x + 24 = 0
x = 0 + 6 or x^2 + 6x + 24 - 0
x = 6
Answer : X = 6

Good luck !
7 0
3 years ago
How many oz of walnuts which cost $6/oz must be added to 2 oz of peanuts which cost $12/oz to make mixed nuts which cost $8/oz
Burka [1]

Answer:  4 oz

<u>Step-by-step explanation:</u>

Create a table.  Multiply across and add down (the middle column cannot be added).  The Mixture line creates the equation that must be solved.

Let x represent the unknown quantity of walnuts.

\begin{array}{c|c|c||c}&\underline{Quantity}&\underline{Cost}&\underline{Qty \times Cost}\\Walnuts&x&6&6x\\\underline{Peanuts}&\underline{\qquad 2\qquad}&\underline{\qquad 12\qquad}&\underline{\qquad 24\qquad }\\Mixture&x+2&8&6x+24\end{array}

.\qquad \qquad \qquad \qquad (x+2)(8) = 6x+24\\.\qquad \qquad \qquad \qquad 8x + 16 = 6x + 24\longrightarrow \text{distributed}\\.\qquad \qquad \qquad \qquad2x+16=24\qquad \longrightarrow \text{subtracted 6x}\\.\qquad \qquad \qquad \qquad 2x=8\qquad \qquad \ \longrightarrow \text{subtracted 16}\\.\qquad \qquad \qquad \qquad x=4\qquad \qquad \quad \longrightarrow \text{divided by 2}

4 0
3 years ago
PLEASE ANSWER WITH AN EXPLANATION! THANK YOU
lubasha [3.4K]

Answer:

\large\boxed{A=153\ cm^2}

Step-by-step explanation:

<em>Look at the picture.</em>

We have

square with side length a = 9

trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6

right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6

The formula of an area of a square

A=a^2

Substitute:

A_I=9^2=81\ cm^2

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2

The formula of an area of a right triangle:

A=\dfrac{l_1l_2}{2}

Substitute:

A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2

The area of the shape:

A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2

8 0
3 years ago
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