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luda_lava [24]
3 years ago
13

If the length of a side of a square is increased from 4 to 8, which of the following statements is true?

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

C.) The perimeter is doubled and the area is quadrupled.

Step-by-step explanation:

Original square: side = 4

Area = side^2 = 4^2 = 16 square units

Perimeter = 4 * side = 4 * 4 = 16 units

Larger square: side = 8

Area = side^2 = 8^2 = 64 square units

Perimeter = 4 * side = 4 * 8 = 32 units

Comparison of areas:

(larger square area)/(original square area) = 64/16 = 4

Comparison of perimeters:

(larger square perimeter)/(original square perimeter) = 32/16 = 2

Answer:

C.) The perimeter is doubled and the area is quadrupled.

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Answer:

To find the inverse of:

f (x)=\dfrac{4}{x-2}-1

Set the function to y:

\implies y=\dfrac{4}{x-2}-1

Rearrange to make x the subject:

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\implies (y+1)(x-2)=4

\implies xy-2y+x-2=4

\implies xy+x=2y+6

\implies x(y+1)=2y+6

\implies x=\dfrac{2y+6}{y+1}

Swap x and y:

\implies y=\dfrac{2x+6}{x+1}

Change y to the inverse of the function sign:

\implies f\:^{-1}(x)=\dfrac{2x+6}{x+1}

Rewrite g(x) as a fraction:

g(x)=\dfrac{3}{x+2}-2

\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}

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\implies g(x)=\dfrac{3-2x-4}{x+2}

\implies g(x)=-\dfrac{2x+1}{x+2}

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other

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2 years ago
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Step-by-step explanation:

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