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3 years ago

a knife set is on sale for $36, the set was on sale for 25% OFF. what was the original total price of the knife set?

Mathematics

1 answer:

erik [133]3 years ago

7 0

The original price was $48

If 75% was 36, divide it by three to get 12 then multiply 12 by 4 to get 100% = 48

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Arithmetic sequence find the next next term in the sequence 44, 51, 58, 65

brilliants [131]

The general term of the number sequence is +7 therefore the next teem would be 65+7=72

7 0

4 years ago

mr.wilson saved 2,500 to buy airlines tickets he bought airline tickets for $372 each how much savings does mr.wilson after he b

ozzi

2,500 subtracted by 372 equals 2148. 2148 dollars is how much savings he has left.

7 0

4 years ago

Read 2 more answers

The diameter of the sun is about 1,391,000 kilometers, and the diameter of Venus is about 12,100 kilometers. About how many time

frez [133]

Answer:

Step-by-step explanation:

Given the following;

Diameter of the sun ds = 1,391,000 kilometers

Diameter of the Venus dv = 12,100kilometers

Taking the ratio of both diameters;

Ratio = Diameter of sun/Diameter of Venus

Ratio = 1,391,000/12,100

Ratio = 13910/121

Ratio = 114.958

Hence ds/dv = 114.958

ds/dv = 1.149 *10^2

ds/dv = 1.15*10^2

ds = 1.15*10^2 dv

Hence the diameter of the sun is 1.15*10^2 larger than that of the venus.

6 0

3 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$