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avanturin [10]
4 years ago
5

Solve the following system of equations.

Mathematics
1 answer:
sasho [114]4 years ago
4 0
X is  minus 2
y is equal to 1
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Multiple the polynomial (4x^2 + 4x + 6)(7x + 5)
Mazyrski [523]

Answer:

28 x³ + 48 x² + 62 x + 30

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the polynomial equation

            (4 x² + 4x +6)(7x+5)

Multiply

   ⇒   4 x² ( 7 x+5) + 4 x ( 7x+5) + 6 (7x+5)

  ⇒    28 x³ + 20 x² + 28 x² + 20 x + 42 x + 30

  ⇒    28 x³ + 48 x² + 62 x + 30

               

8 0
3 years ago
What is the value of Negative 3 m n + 4 m minus 3 when m = 2 and n = negative 4?
Ivanshal [37]

Answer:

Step-by-step explanation:

-3(2)(-4)=24

24+4(2)=32

32-3=29

5 0
3 years ago
Divide and simplify.
vredina [299]

Answer:

\frac{ {x}^{2} + 10x + 16 }{ {x }  {}^{2}  + 6x + 8} \div  \frac{1}{x + 2}

\frac{ {x}^{2} + 8 x+  2x + 16}{ {x}^{2}  + 4x + 2x + 8}  \times (x + 2)

\frac{x(x + 8) + 2 (x + 8)}{x(x + 4) + 2(x + 4)}  \times (x + 2)

\frac{( x + 8)(x + 2)}{(x + 2)(x + 4)}  \times ( x + 2)

\frac{( x + 8)(x + 2)}{(x + 4)}

3 0
3 years ago
A 9 in the thousandths place has 10 times the value of a 9 in the ? Place.
Shtirlitz [24]

Answer:

hundredths place

7 0
3 years ago
Read 2 more answers
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
masha68 [24]

Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

We note that the volume of a cone = \dfrac{1}{3} \cdot A_b \cdot h

Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

4·h = 150

h = 150/4 = 37.5 cm

The height of the cone = 37.5 cm

4) The storage area at the back corner  with four sides = 100 m²

The storage area at the back of the building with three sides = 98 m²

Given that the available riling = 28 m, we have;

For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

5 0
4 years ago
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