Ask question

Ask question

All categories

2 years ago

9

Someone help me plzz

1 answer:

galina1969 [7]2 years ago

5 0

Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
-1/5 * x = -1
x = -1/-1/5
x = 5
The equation perpendicular to y=-1/5x-3 is y=5x-c
Now it contains the points (1,2)
x variable is 1 and y variable is 2 plug them into the line equation
2=5(1)-c
2=5-c
2-5=-c
-3=-c divide by -1
3=c
Hence the perpendicular equation is y=5x+3
Hopefully it’s correct :)

You might be interested in

What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.

Anit [1.1K]

The equation of the line is, $\rm y = 3x + 1$ .

Given that,

The equation of the line is,

$\rm y = \dfrac{1}{3} x+4\\$

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

$\rm = \dfrac{1}{3}x + 4\\$

On comparing with the standard equation of the line y = mx +c.

The slope of the line $m_1$ is 1/3.

When two lines are perpendicular the relation between these slopes is,

$\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3$

And line contains the point (-2, -5).

Then,

$\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1$

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

$\rm y = mx +c \\\\y = 3x +1$

Hence, The required equation of the line is, $\rm y = 3x + 1$ .

For more details refer to the link given below.

brainly.com/question/14388443

7 0

2 years ago

PLEASE HELP ITS URGENT

Cerrena [4.2K]

Step-by-step explanation:

6 0

2 years ago

Solve to find x 3/4 (5x-3) + 8 = 17

Talja [164]

Answer:

3

Step-by-step explanation:

3/4 (5x -3)+8=17

3/4 (5x -3) = 17 - 8 = 9

(5x -3) = 9 * (4/3)= 36/3 = 12

5x = 12 + 3 = 15

x = 3

6 0

3 years ago

Write a polynomial equation with roots 5 and -9i. X^3-?x^2+?X-?=0

jek_recluse [69]

Answer:

x³ - 5x² + 81x - 405 = 0

Step-by-step explanation:

Complex roots occur in conjugate pairs.

Thus given x = - 9i is a root then x = 9i is also a root

The factors are then (x - 5), (x - 9i) and (x + 9i)

The polynomial is the the product of the roots, that is

f(x) = (x - 5)(x - 9i)(x + 9i) ← expand the complex factors

= (x - 5)(x² - 81i²) → note i² = - 1

= (x - 5)(x² + 81) ← distribute

= x³ + 81x - 5x² - 405, thus

x³ - 5x² + 81x - 405 = 0 ← is the polynomial equation

6 0

3 years ago

9x+8y=6<br>-7x=14<br>what is the system of equation by elimination?

Pavlova-9 [17]

9x-7x= 2x
because both are x's now u cant add nor subtract anything to Y so just leave it alone but u can add 6+14

2x+8y=20

5 0

3 years ago