Question

Given f(x) = 4+1 , describe how the graph of g compares with compares with the graph of f?

Answer 1

I think you wrote an incomplete question. With a little research, I was able to find a question similar to you which is attached below. So, I would solve your question based on the question attached below, which anyways would clear your concept.

Answer:

$g(x)$ is the graph of $f(x)$ translated left $3$ units. Also, the comparison graph is attached below.

Step-by-step explanation:

Considering the complete question attached below

Given the function

$f\left(x\right)\:=\:4x+1$

As for $g(x)=f(x-h)$, the graph of $g(x)$ is the graph of $f(x)$ translated right h units when '$h$' is greater than zero, and left | $h$ | units when h is lesser than zero.

so it is clear if  

$g(x)=4(x+3)+1$ and $f\left(x\right)\:=\:4x+1$, then $g(x) = f(x+3)$.

Hence, $h = -4$ ( lesser than zero i.e. h < 0).

Therefore, $g(x)$ is the graph of $f(x)$ translated left $3$ units. Also, the comparison graph is attached below.