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m_a_m_a [10]
3 years ago
6

The flagpole in Terry's schoolyard is 50 ft tall. On a sunny day, the flagpole casts a shadow 30 ft long on level ground. What i

s the angle of depression from the top of the flagpole to the path of the sun's rays? Round to the nearest tenth of a degree.
A.61
B.59
C.60
D.62
Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

64.5°

Step-by-step explanation:

it is the answer got it nd comment me

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A patient requires an IV of D5W, a 5% solution of dextrose (sugar) in water. To the nearest milliliter, how much D20W, a 20% sol
solmaris [256]

Answer:

  A=300ml

Step-by-step explanation:

From the question we are told that

5% solution of dextrose sugar in water

20% solution of dextrose in

100 milliliters of distilled water water

Generally in mathematically solving we call A the amount of D20W added

Since 20% of dextrose is needed

       20 \%*100=20milliter

Total quantity after addition (100+x)

for DW5% total solution is

          5\% (100+A)= \frac{5}{100}(100+A)

          5\% (100+A) =5+0.05A

Mathematically

           5+0.05A =20

           5+0.05A =20-5

           A=\frac{15}{0.05}

           A=300ml

Therefore the required quantity A=300ml

7 0
3 years ago
How do you write four million, six hundred five thousand in standard form
natima [27]
Your answer will be 4,605,000
7 0
3 years ago
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Square root of 81x - square root of 25x
vova2212 [387]
The square root of 81 is 9. The square root of 25 is 5.
5 0
4 years ago
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A forest covers 52000 acres. A survey finds that 0.4​% of the forest is​ old-growth trees. How many acres of​ old-growth trees a
maxonik [38]

Given:

Total forest area = 52000 acres

Area of old growth trees in the forest = 0.4%

To find:

The area of old growth trees.

Solution:

We have,

Total forest area = 52000 acres

Area of old growth trees in the forest = 0.4%

Area of old growth trees is

Area=0.4\% \text{ of total forest area}

Area=\dfrac{0.4}{100}\times 52000

Area=0.4\times 520

Area=208

Therefore, the area of old growth trees is 208 acres.

4 0
3 years ago
Two sides of a parallelogram measure 60 centimeters and 40 centimeters. If one angle of the parallelogram measures 132, find the
Serjik [45]
By cosine rule, the length of the longer diagonal is sqrt(60^2 + 40^2 - 2 x 60 x 40 cos 132) = sqrt(8,411.83) = 91.7 cm

The other angle of the parallelogram is 180 - 132 = 48
The length of the shorter diagonal is sqrt(60^2 + 40^2 - 2 x 60 x 40 cos 48) = sqrt(1,988.17) = 44.6 cm
7 0
3 years ago
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