Question

At​ noon, a tank contained 5 cm of water. After several​ hours, it contained 4 cm of water. What is the percent decrease of water in the​ tank?

Answer 1

Answer:

20%

Step-by-step explanation:

Given parameters:

Initial volume of water = 5cm³

New volume of water = 4cm³

Unknown:

Percentage decrease of water in the tank = ?

Solution:

To find the percentage decrease;

  Percentage decrease  = $\frac{Old - New}{Old}$ x 100

 Percentage decrease  = $\frac{5-4}{5}$ x 100  = 20%