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Lana71 [14]
3 years ago
10

At​ noon, a tank contained 5 cm of water. After several​ hours, it contained 4 cm of water. What is the percent decrease of wate

r in the​ tank?
Mathematics
1 answer:
diamong [38]3 years ago
8 0

Answer:

20%

Step-by-step explanation:

Given parameters:

Initial volume of water = 5cm³

New volume of water = 4cm³

Unknown:

Percentage decrease of water in the tank = ?

Solution:

To find the percentage decrease;

  Percentage decrease  = \frac{Old - New}{Old} x 100

 Percentage decrease  = \frac{5-4}{5} x 100  = 20%

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