Question

A patient requires an IV of D5W, a 5% solution of dextrose (sugar) in water. To the nearest milliliter, how much D20W, a 20% solution of dextrose in water, must be added to 100 milliliters of distilled water to produce a D5W solution? Please show all work.

Answer 1

Answer:

  $A=300ml$

Step-by-step explanation:

From the question we are told that

5% solution of dextrose sugar in water

20% solution of dextrose in

100 milliliters of distilled water water

Generally in mathematically solving we call A the amount of D20W added

Since 20% of dextrose is needed

       $20 \%*100=20milliter$

Total quantity after addition (100+x)

for DW5% total solution is

          $5\% (100+A)= \frac{5}{100}(100+A)$

          $5\% (100+A) =5+0.05A$

Mathematically

           $5+0.05A =20$

           $5+0.05A =20-5$

           $A=\frac{15}{0.05}$

           $A=300ml$

Therefore the required quantity $A=300ml$