All real numbers is the correct answer.
Answer:
sex kaise kare aur bata ky chal raha tha aur bata ky chal raha h
Answer:
No
Step-by-step explanation:
Translation only moves a shape from one spot to another.
Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
Yes, it is true that 
is a factor of 
.
Step-by-step explanation:
Let us try to factorize
Let us try to make a whole square of the given terms:
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Formula used above:
In the above equation, we had 
.
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Further solving the above equation, taking 
common out of 
Taking 
common out of the above term:
So, the two factors are 
.
The statement that is a factor of is <em>True.</em>
