Answer:
<h2>
1/9</h2>
Step-by-step explanation:
Given the sample space of a die S=(1,2,3,4,5,6)
and the sample size=6
the probability of obtaining the number 1 Pr(1)= 1/6= 1/6
the probability of obtaining the number 6 Pr(1)= 6/6= 1
the probability of obtaining the number 4 Pr(1)= 4/6= 2/3
Hence the probability of P(1,6,4) = 
Answer:
V≈904.78ft³
Step-by-step explanation:
Answer:
81m²
Step-by-step explanation:
I took the quiz :)
Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
Answer:
a = 2
b = 3
c = 8
Step-by-step explanation:
First, let us look at the first two (far left) fractions to solve for a.
Since
, nothing needs to change in the numerator. 4 = 
a = 2.
Next, we will look at the first and third fractions to solve for b.
= 32
32 / 4 = 8
= 8
b = 3
Lastly, we will solve for c.
All of these fractions simplify to 8 and are equal to each other.
c = 8