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Dima020 [189]
2 years ago
5

PLSSS I NEED HELP VERY QUICKLY!!!!!!!!!!

Mathematics
1 answer:
dangina [55]2 years ago
3 0

Answer:

6.7

Step-by-step explanation:

\sqrt(3 ^{2}  + 6 ^{2} )

\sqrt{45}  \\  \\  = 6.7cm

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The first digit of a string of 2002 digits is a 1. Any two-digit number formed by consecutive digits within this string is divis
Umnica [9.8K]

The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

We have to tell the last largest digit of such number.

Two digit numbers divisible by 19=19,38,57,76,95.

Two digit numbers divisible by 31=31,62,93,124

Number started with 1 =19

Last digit is 9

We have said that the number should be divisible by 19 or 31 not from both and started with 1.

Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

Learn more about digits at brainly.com/question/26856218

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4 0
2 years ago
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Bumek [7]

Answer:

Step-by-step explanation:

(C)

5 0
3 years ago
Which expression shows how 6 • 45 can be rewritten using the distributive property?. A. 6 • 40 + 6. B. 6 • 4 + 6 • 5. C. 6 • 40
svlad2 [7]
6*45 =   6*(40 + 5) = 6*40 + 6*5

Option C.
5 0
3 years ago
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Letters that represent numbers are called ?
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i believe its variables

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3 years ago
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Mark is solving the equation 4x2 + 2x = -9 using the quadratic formula.
Masteriza [31]
4x^2 + 2x = -9
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remember that the form of quadratic is ax^2 + bx + c = 0

so
a = 4
b = 2
c = 9
6 0
3 years ago
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