Answer:
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Step-by-step explanation:
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<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
Basic Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify given.</em>
<em />
<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:
Let's first <em>square both sides</em>:

Next, <em>add p to both sides</em>:

Next, <em>divide 4t by both sides</em>:

We can rewrite the new equation by swapping sides to obtain our final expression:

∴ we have <em>changed</em> the subject of the formula.
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Learn more about Algebra I: brainly.com/question/27698547
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Topic: Algebra I
<h3>
Answer :</h3>
x = 5
Step-by-step explanation:
<h3>: Given equation </h3><h3> • 8x + 2 = 42 </h3><h3> 8x = 42 – 2</h3><h3> 8x = 40</h3><h3> x = 40/8 = 5</h3><h3> x = 5</h3>