Options are not shown but…
A square has 4 equal length sides and a right angle
Or two equal length diagonals which are perpendicular
Or 4 right angled corners and two adjacent sides equal
Or perpendicular diagonals with the same midpoint
Using the last one…
Gradient of AC = (5 - 3)/(-3 - 3) = 2/-6 = -1/3
Gradient of BD = (7 - 1)/(1 - -1) = 6/2 = 3
-1/3 x 3 = -1 so AC and BD are perpendicular
Midpoint of AC = ((-3 + 3)/2 , (5 + 3)/2) = (0, 4)
Midpoint of BD = ((1 + -1)/2 , (7 + 1)/2) = (0, 4)
QED
Answer:
1.y=3x-7
2.y=-3x-5
3.y=x+2
4.y=-4x+1
5.y=x+6
6.y=1/2x+5
Step-by-step explanation:
parallel lines have the same slope
1.y-2=3(x-3)
y-2=3x-9
y=3x-9+2
y=3x-7
2.y-(-2)=-3(x-(-1))
y+2=-3x-3
y=-3x-3-2
y=-3x-5
3.y-1=1(x-(-1)
y-1=1(x+1)
y-1=1x+1
y=1x+1+1
y=1x+2
4,y-(-3)=-4(x-1)
y+3=-4x+4
y=-4x+4-3
y=-4x+1
5.y-2=1(x-(-4)
y-2=1(x+4)
y-2=1x+4
y=1x+4+2
y=1x+6
6.y-3=1/2(x-(-4)
y-3=1/2(x+4)
y-3=1/2x+4/2 simplify 4/2 to 2/1 =2
y=1/2x+2+3
y=1/2x+5
16.2 if i’m correct
hope this helps
The answer is letter A and letter D
