Answer:
The answer is x=24.
Step-by-step explanation:
This is a one step equation, so it is simple, as shown.
In order to isolate the variable, you need to multiply each side of the equation by the fraction's reciprocal. In this case, it is -4/5.
Thus, x= -30 x -4/5
All things said, the answer is x=24.
I hope this helped!!
~ Penny
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
Answer:
c = 2
Step-by-step explanation:
From the statement we have that If 14 is 7 times a number c, we can write the following equation:
7c = 14. Solving for c, we have:
c = 14/7 = 2
Yes. That point is in the solution space.
_____
You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution
The value decreases $187.5 a year, hope it helps, please let me know if im right