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Wittaler [7]
2 years ago
8

Got this one wrong need help

Mathematics
1 answer:
elixir [45]2 years ago
6 0
Each angle on a triangle pertains to the opposite side

so let’s start by solving the equations:
6 + 4 = 10
2(6) - 3 = 9
3(6) - 10 = 8

then order then look at what each of the sides is opposite to:

10 = A
9 = B
8 = C

so from smallest to largest the angles are C, B, A
You might be interested in
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
3 years ago
Answers :<br> A:6.6<br> B:7.2<br> C:7.8<br> D8.1
OLga [1]

Answer:

approx 7.81 Exactly: √61

Step-by-step explanation:

Use Pythag theorem: 5^2 + 6^2 = hyp^2 (line AS)

25 + 36 = 61

hyp = √61 or about 7.81

8 0
2 years ago
Divide (8.6 x 108) by (3.2 x 103). express your answer in scientific notation
spin [16.1K]
(8.6 x 108) x (3.2 x103

place them in order

(8.6 x  3.2)  x (108 x 103)
 
27.52 x (108 x 103)

27.52 x 11124

 That is your answer to this question.
7 0
3 years ago
Some1 hurry up plzzz need help
Step2247 [10]

Answer:

IM pretty sure b) and c)

Step-by-step explanation:

3 0
2 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
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