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3 years ago

Find the vertex this parabola y = -x^2 - 2x + 6

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

Y=-x^2-2x+6
To find the vertex I'm going to use the axis of symmetry formula:
x=-b/2a
x = 2/-2
x = -1
To find the y-value I'm going to plug in the x value in the above equation
y=-(-1)^2-2(-1)+6
y = -1+2+6
y = 7
The vertex is :
(-1,7)

:D :D :D

Charra [1.4K]3 years ago

4 0

Your answer will be (-1,7)

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Marta_Voda [28]

Answer:

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Step-by-step explanation:

A. Since we know the diagonals of an isosceles trapezoid are congruent, we know that the two bottom parts of the diagonal BD (2x - 8 and x - 4) are congruent to the diagonal AC (x + 2) . This means you can just equal them together and get the value of x:

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