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Readme [11.4K]
3 years ago
11

Find the vertex this parabola y = -x^2 - 2x + 6

Mathematics
2 answers:
miskamm [114]3 years ago
7 0
Y=-x^2-2x+6 
To find the vertex I'm going to use the axis of symmetry formula: 
x=-b/2a 
x = 2/-2 
x = -1 
To find the y-value I'm going to plug in the x value in the above equation 
y=-(-1)^2-2(-1)+6 
y = -1+2+6 
y = 7 
The vertex is : 
(-1,7) 

:D :D :D 
Charra [1.4K]3 years ago
4 0
Your answer will be (-1,7)
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Four times the greater of two consecutive integers is 18 more than three times the lesser integer. What are the integers?
maw [93]
This is how I would solve it:

1st # = x                 4(x+1)=3x+18
2nd # = x+1              4x+4=3x+18
                                     4x=3x+14
                                       x=14

To check: 15x4=60; 60-42=18.       <u>1st # = 14; 2nd # = 15.</u>
5 0
3 years ago
A projectile is launched upward from a height of 704 feet with an initial velocity of 112 ft/s. The equation gives the height h
Feliz [49]
We are given the data ho equal to 704 feet and vo equal to 112 feet per second. We apply then kinematics equation: h = ho + vot - 1/2 gt2. Substituting to the given equation, 
h = 704 + 112t - 1/2 * 32*t2when h is equal to zero,0 = 704 + 112t - 1/2 * 32*t2t is equal to 11 seconds
4 0
3 years ago
In the Acronym WKU, what does each letter represent?
marin [14]

Answer:

Western Kentucky University

Step-by-step explanation:

Western Kentucky University is a public university in Bowling Green, Kentucky. It was founded by the Commonwealth of Kentucky in 1906, though its roots reach back a quarter-century earlier. It operates regional campuses in Glasgow, Elizabethtown-Fort Knox, and Owensboro.

3 0
3 years ago
Read 2 more answers
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Alex

135inches2

Step-by-step explanation:

by multiplying both length and width you can get the sum

8 0
2 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
3 years ago
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