Answer: ABCD is a parallelogram.
Step-by-step explanation:
First we plot these point on a graph as given in attachment.
From the attachment we can observe that AD || BC || x-axis .
also, AB ||CD, that will make ABCD a parallelogram , but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".
Mid point of AC= 
Mid point of BD= 
Thus, Mid point of AC=Mid point of BD
i.e. diagonals bisect each other.
That means ABCD is a parallelogram.
<h3>
Answer:</h3><h3>If you know one ratio in a proportion , you can use that information to find values in the other equivalent ratio. </h3>
0<4x + 8<12 BADDA-BING-BADDA-BOOM!!! :-)
Answer:
JK ≅ MN
Step-by-step explanation:
SAS states that any two sides of the angle and the angle itself, if , of two triangles are equal the two triangles are equal.
It is given that ∠J ≅ ∠M and JL ≅ MR i.e an angle and a side are equal. We need one more side to prove that the two triangles are equal.
If we look at the diagram closely we see that the angles J and M are formed by the sides JK & JL and MN& MR.
It is given that JL ≅ MR so we are left with JK ≅ MN
Answer:
15.98
Step-by-step explanation:
∑₁¹⁰ 
![=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]](https://tex.z-dn.net/?f=%3D8%5B1%2B%5Cfrac%7B1%7D%7B4%7D%20%2B%5Cfrac%7B1%7D%7B16%7D%20%2B%20........%20%2Bt_%7B10%7D%5D)
We have to use the formula of sum of a G.P. series with common ratio r < 1.
If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by
![[a \times\frac{1-r^{n} }{1-r}]](https://tex.z-dn.net/?f=%5Ba%20%5Ctimes%5Cfrac%7B1-r%5E%7Bn%7D%20%7D%7B1-r%7D%5D)
![= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]](https://tex.z-dn.net/?f=%3D%208%5B1%20%5Ctimes%20%5Cfrac%7B1-%5Cfrac%7B1%7D%7B2%5E%7B10%7D%20%7D%20%7D%7B1-%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5D)
(Answer)
